You are searching about *What Does Proportional Mean In Math*, today we will share with you article about What Does Proportional Mean In Math was compiled and edited by our team from many sources on the internet. Hope this article on the topic **What Does Proportional Mean In Math** is useful to you.

## Supercharger Calculators Explained

The Basics of Boost Calculators…

Supercharger calculators are based on several basic equations that govern performance and the physical rules that bind superchargers. At the very heart of the matter, boosters operate on the ideal gas law where PV = NRT pressure x volume = number of gas molecules X a constant temperature X. What superchargers do is they feed the engine with more air molecules, by feeding the engine with forced air. This air is forced into the engine because the compressor blows more air into the engine inlet than the engine would normally breathe under its own apparatus. The result of this “forced induction” can be observed and measured in one of two aspects: pressure or temperature. In an ideal world, with a compressor that has perfect adiabatic efficiency, we are able to feed the engine twice as many air molecules (to double the power), by doubling the intake air pressure (to 2.0 atmosphere or what we call 15 pounds per square inch (PSI) of boost). In the real world, superchargers aren’t 100% efficient, so it’s possible that doubling the intake boost pressure will give us less than double the power due to the following:

P*V=n*R*T Pressure increases by a factor of 2 Volume is fixed Number of gas molecules increases by 80% (or by a factor of 1.8) Temperature increases by a factor of 11% (or by a factor of 1.11) If we look at our equation above, we can see: 2*P*V = 1.8*N*R* 1.11T The equation is balanced as 2 .0X1 = 1.8 * 1.11 (the increase in pressure is equal to the combined effect of the increase in airflow and the rise in temperature).

From this we can also see that even at the same ‘boost’ level, a more efficient compressor can generate more power because more of the compressor’s energy is translated into compression and airflow. air rather than thermal lift… So how do we bring these equations into the “real world” in terms of power and boost? Let’s start with a 2.0 liter engine (volume) and 140 hp (air molecules). Let’s say we have a goal of 280 horsepower. Our flow ratio will be related to the ratio of our target power to our current power…. Density ratio = 280 / 140 = 2.0 Density = mass / volume and since the engine volume is fixed at 2.0 liters, then we need to fit 2.0 times the mass of air into the same volume. This means that we have to fit twice as many air molecules into the engine. Now suppose we have a compressor that is 70% efficient. This means that to achieve a density ratio of 2.0, we need a pressure ratio: P = 2.0 / 0.70 = 2.85 A pressure ratio of 2.85 equals 27 psi. If we instead look at the temperature rise… then T2/T1 = Pressure ratio / Density ratio So compressor outlet temperatures T2 = Pressure ratio (P) / Density ratio * T1 (where temperature is in degrees Kelvin).

Assuming an inlet temperature of 80*F, we find that the compressor outlet temperature is T2 = 309*F. The thing to think about here is the intercoolers or aftercoolers…. After the coolers are radiators that remove heat from compressed air after it leaves the compressor. The ideal intercooler significantly cools the air temperature without significantly impeding the airflow path and therefore with minimal pressure drop. The intercooler increases power in three ways:

1 – By cooling the air charge, the density ratio of the mixture increases at the same pressure ratio.

2 – The final temperature of the air-fuel mixture entering the engine drops, resulting in a more efficient combustion process (because the power output of the combustion event is directly proportional to the difference between the temperatures of the fuel mixture intake and exhaust mixture temperatures).

3 – Lowering the final octane requirements of the mix, allowing us to add more timing advance or more boost pressure, and make more power within the same octane limits.

With a good intercooler, we are able to lower the air intake charge temperature to within 30 degrees of the ambient air temperature. At the same time, an intercooler will only have a marginal pressure drop of 0.5 to 1.0 psi across the core. With those numbers in mind, combining a supercharger with an efficient intercooler gives us a system that has adiabatic efficiency much closer to 100%, and that means we’re able to double our engine power. stock at about 18 psi of boost (instead of 27 without the intercooler, and instead of 15 for an “ideal” supercharger) if you care to follow the math behind this scenario.

Once you have your pressure ratio, density ratio, your intercooler outlet temperatures and your overall horsepower and flow values, most compressor calculators are then able to give you more detailed specifications. for your car’s build (such as exact compressor gear figures and required intake). and exhaust dimensions, as well as fuel pressure or flow upgrade requirements). But at the heart of any supercharged or turbocharged vehicle, PV=nRT will always be true. This is great information to know, as several people have chosen to try and sell water scavenging pumps typically used on boats as “electric” boosters for small displacement engines. It has been repeatedly shown that by fitting a boost gauge to the inlet of one of these “electrically supercharged” engines, these bilge pumps do not have the flow rate or blocking pressure capability to increase the boost pressure of the inlet mixture by any measurable amount. . Pressure (as we explained earlier) is not the only indication of forced induction…but with no pressure increase at all, it means the “electric” compressor has 0% efficiency, which which means that at best it will only heat up the intake air and no excessive airflow will be observed.

## Video about What Does Proportional Mean In Math

You can see more content about **What Does Proportional Mean In Math** on our youtube channel: Click Here

## Question about What Does Proportional Mean In Math

If you have any questions about **What Does Proportional Mean In Math**, please let us know, all your questions or suggestions will help us improve in the following articles!

The article **What Does Proportional Mean In Math** was compiled by me and my team from many sources. If you find the article What Does Proportional Mean In Math helpful to you, please support the team Like or Share!

## Rate Articles What Does Proportional Mean In Math

**Rate:** 4-5 stars

**Ratings:** 2506

**Views:** 90825715

## Search keywords What Does Proportional Mean In Math

What Does Proportional Mean In Math

way What Does Proportional Mean In Math

tutorial What Does Proportional Mean In Math

What Does Proportional Mean In Math free

#Supercharger #Calculators #Explained

Source: https://ezinearticles.com/?Supercharger-Calculators-Explained&id=3201927